Hello,

I simply love the "not so easy" game mechanics.

Therefore the beginnings are quite hard.

(5th attempt and bankrupt

*again*).

It will help if one could plan a bit the costs before running a convoy.

Here I would need your help. Search the forum and wiki gave me 3 informations :

- 100 km per hour is equivalent to 1024 tiles per mounth (wiki ? ingame help?)
- pak 128 brit : 2.75 mounth = 1 day; 16h per day => scale is 76:1 (source)
- vehicules have a running cost per km

Let's start with two industries located in (107,339) and (162,308). Coordinates should give the number of tiles between two points (direct flying route). After calculation :

**63 tiles**. First run with a 1912Benz :

-228 euros. Cost per km : 2.72. So 228/2.72 =

**83 km**.

First problem : ok the truck hit the road, not a direct route, but the detour was not big. So 63 tiles (direct) = 83 ? tiles (road)= 83 km (route).

**1 tile = 1 km **?? (does not look like it)

I tryed then to go with timing the convoy. The 1912Benz runs at

**30 km/h**. Start at (107,339) : 9 mai 2h, arrival at (162,308) : 15 mai 17h. In game time travel :

**159 h** (6.6 days).

Real time travel : 83 km at 30 km/h :

**2.8** h

Scale : 159 h/2.8h =>

**56:1**It seems close to the 76:1 mentioned

here. It was for another pak, and I run with the pak128.

Can I get a approximation of the equavalence tile/km with this scale for time?

Last method : in game indication of time travelled. One run is indeed 83 km (a trip of 166 km, back and forth). During a month : 387 km. That's 387/83 = 4.6 run a month. 30 days/4.6 = 6.5 days a run. Close to the 6.6 days above.

Too long to read?Is 1 tile approx. 1 "real" km?

Is 60h in game approx. 1 "real" hour?